Comment calculer les frais de Tezos

Je calcule demanièreprogrammée lesfrais detransaction.

Afaik,Bakerspar défaut adhère au calcul desfrais suivants:

 frais >=(minimal_fees +minimal_nanotez_per_byte * Taille +minimal_nanotez_per_gas_unit * Gaz)
 

où

 minimal_fees=0.000 1ꜩ (100μꜩ)
minimal_nanotez_per_gas_unit=100nꜩ/gu (0.000 000 1ꜩ/GU)
minimal_nanotez_per_byte=1000nꜩ/B (0.000 001ꜩ/b)
 

( Source )

Aujourd'hui,j'aieu un transaction qui aexpiré dans lamémoire MEMPOOL . Latransaction a utilisé 66754 unités degazet 234 octets de stockage.

Sur labase de ce quiprécède,je pense que lesfraisproposés de 0,00701XTZ auraient dû être suffisantspour êtreinclus dans unbloc:

  Fraisminimaux=.000001
Frais degaz=66745 * 100nꜩ/gu=.006676 (arrondi)
Frais de stockage=234 * 1000nꜩ/B=.000234
--------------------------------------------------
Total=.00701
 

Pourquoi cettetransactionn'a-t-ellepas étéincluse dans unbloc?

I am programatically calculating fees for transactions.

AFAIK, bakers by default adhere to the following fee calculation:

fees >= (minimal_fees + minimal_nanotez_per_byte * size + minimal_nanotez_per_gas_unit * gas)

where

minimal_fees = 0.000 1ꜩ (100µꜩ)
minimal_nanotez_per_gas_unit = 100nꜩ/gu (0.000 000 1ꜩ/gu)
minimal_nanotez_per_byte = 1000nꜩ/B (0.000 001ꜩ/B)

(Source)

Today, I had a transaction which timed out in the mempool. The transaction used 66754 gas units and 234 bytes of storage.

Based on the above, I think that the proposed fee of 0.00701XTZ should have been sufficient to get included in a block:

minimal fees =                     .000001
gas fees     = 66745 * 100nꜩ/gu =  .006676  (rounded up)
storage fees = 234 * 1000nꜩ/B   =  .000234 
----------------------------------------------
total        =                     .00701

Why was this transaction not included in a block?