AJAX - Retour de deux objets JSON avec une fonction PHP

Question

AJAX - Retour de deux objets JSON avec une fonction PHP

0

44421 2013-07-26

Commentpourrais-je retourner deux objets JSON avec un appel AJAXet unefonction PHP? Toute aideesttrès appréciée!

Voici lafonction PHP:

 function get_ldap_attr() {
    header("Content-type: application/json");
    $lan = $_POST['lan'];
    $dn = get_site_option ( "ldapServerOU" );
    $usr = get_site_option ( "ldapServerCN" );
    $pw = get_site_option ( "ldapServerPass" );
    $addr = get_site_option ( "ldapServerAddr" );
    $ad = ldap_connect ( $addr )
        or die ( "Connection error." );
    ldap_set_option ( $ad, LDAP_OPT_PROTOCOL_VERSION, 3 );
    ldap_set_option ( $ad, LDAP_OPT_REFERRALS, 0 );
    $bind = ldap_bind ( $ad, $usr, $pw );
    if ( $bind ) {
        $SearchFor ="cn=".$lan;
            $result = ldap_search ( $ad,$dn,$SearchFor );
            $entry = ldap_first_entry ( $ad, $result );
            if ( $entry != false )  {
                $info = ldap_get_attributes ( $ad, $entry );
            }           
            $comm  = stripos ( $info['manager'][0], ',' );
                // find position of first comma in CN=Mxxxxxx,OU=Users,OU=MCR,DC=mfad,DC=mfroot,DC=org  (directReports field)
            $eq = stripos ( $info['manager'][0], '=' );
                // find position of first =
            $s_lanid = substr ( $info['manager'][0], $eq+1, ( ( $comm-1 ) - ( $eq ) ) );
                //get substring between = and comma... for lanid happiness..
            $sup = getLDAPInfo ( $s_lanid, $bind, $ad, $dn ); 
                // get supervisor's info...
    }

    echo json_encode($sup);
    die();  
}

Et lejQuery:

 jQuery(function() {
    jQuery('#empLanId').on('blur', function() {
        var lan = jQuery('#empLanId').val();
        var ajaxurl = '<?php echo admin_url("admin-ajax.php", null); ?>';
        var data = { action: "get_ldap", lan: lan};
        jQuery.ajax({
            type: 'POST',
            url: ajaxurl,
            data: data,
            dataType: 'json',
            success: function(response) {
                jQuery('#empSupLanId').val(response.lanid);
                jQuery('#empSupName').val(response.fullname);
                jQuery('#empSupNumber').val(response.phone);
            }
        });
    });
});

How would I go about returning two JSON objects with one AJAX call and PHP function? Any help is much appreciated!

Here's the PHP function:

function get_ldap_attr() {
    header("Content-type: application/json");
    $lan = $_POST['lan'];
    $dn = get_site_option ( "ldapServerOU" );
    $usr = get_site_option ( "ldapServerCN" );
    $pw = get_site_option ( "ldapServerPass" );
    $addr = get_site_option ( "ldapServerAddr" );
    $ad = ldap_connect ( $addr )
        or die ( "Connection error." );
    ldap_set_option ( $ad, LDAP_OPT_PROTOCOL_VERSION, 3 );
    ldap_set_option ( $ad, LDAP_OPT_REFERRALS, 0 );
    $bind = ldap_bind ( $ad, $usr, $pw );
    if ( $bind ) {
        $SearchFor ="cn=".$lan;
            $result = ldap_search ( $ad,$dn,$SearchFor );
            $entry = ldap_first_entry ( $ad, $result );
            if ( $entry != false )  {
                $info = ldap_get_attributes ( $ad, $entry );
            }           
            $comm  = stripos ( $info['manager'][0], ',' );
                // find position of first comma in CN=Mxxxxxx,OU=Users,OU=MCR,DC=mfad,DC=mfroot,DC=org  (directReports field)
            $eq = stripos ( $info['manager'][0], '=' );
                // find position of first =
            $s_lanid = substr ( $info['manager'][0], $eq+1, ( ( $comm-1 ) - ( $eq ) ) );
                //get substring between = and comma... for lanid happiness..
            $sup = getLDAPInfo ( $s_lanid, $bind, $ad, $dn ); 
                // get supervisor's info...
    }

    echo json_encode($sup);
    die();  
}

And the jQuery:

jQuery(function() {
    jQuery('#empLanId').on('blur', function() {
        var lan = jQuery('#empLanId').val();
        var ajaxurl = '<?php echo admin_url("admin-ajax.php", null); ?>';
        var data = { action: "get_ldap", lan: lan};
        jQuery.ajax({
            type: 'POST',
            url: ajaxurl,
            data: data,
            dataType: 'json',
            success: function(response) {
                jQuery('#empSupLanId').val(response.lanid);
                jQuery('#empSupName').val(response.fullname);
                jQuery('#empSupNumber').val(response.phone);
            }
        });
    });
});

3 réponses

votes

1

2018-11-07

CodejQuery:

 (function ($) {
    'use strict';
    $(function () {
        var value_1 = 10;
        var value_2 = 20;
        $('.btn').on('click', function(){
            $.ajax({
                url: 'your_ajax_url_here',
                type: 'POST',
                data: {
                    action  :   'action_name',
                    val_1   :   value_1,
                    val_2   :   value_2,
                },
                beforeSend: function () {
                    console.log('Sending....');
                },
                success: function (response) {
                    var obj = JSON.parse(response);
                    console.log(obj);
                },
                error: function (errorThrown, status, error) {
                    console.log( status );
                }
            });
        })
    });
})(jQuery);

Code PHP:

 function get_ldap_attr() {

   $obj_val_1 = $_POST['val_1'];
   $obj_val_2 = $_POST['val_2'];

   echo json_encode(array(
       'obj_1' => $obj_val_1,
       'obj_2' => $obj_val_2,
   ));

}

C'esttout.

jQuery Code:

(function ($) {
    'use strict';
    $(function () {
        var value_1 = 10;
        var value_2 = 20;
        $('.btn').on('click', function(){
            $.ajax({
                url: 'your_ajax_url_here',
                type: 'POST',
                data: {
                    action  :   'action_name',
                    val_1   :   value_1,
                    val_2   :   value_2,
                },
                beforeSend: function () {
                    console.log('Sending....');
                },
                success: function (response) {
                    var obj = JSON.parse(response);
                    console.log(obj);
                },
                error: function (errorThrown, status, error) {
                    console.log( status );
                }
            });
        })
    });
})(jQuery);

PHP Code:

function get_ldap_attr() {

   $obj_val_1 = $_POST['val_1'];
   $obj_val_2 = $_POST['val_2'];

   echo json_encode(array(
       'obj_1' => $obj_val_1,
       'obj_2' => $obj_val_2,
   ));

}

That's all.

0

2018-07-26

 <script type="text/javascript">
  $(document).ready(function(){

    //jquery script
    $("#emp_mat").change(function(){

      var emp_mat = $(this).val();
    $.ajax({
        url:"emp_info.php",
        dataType:'json',
        data:{data:emp_mat}
      }).done(function(result)
      {
        $("#nom_prenom").val(result[0]);
        $("#adresse").val(result[1]);

      })
    });

  });
</script>

<input type="text" id="nom_prenom"   disabled="true" size="58"/>
<input type="text" id="adresse"   disabled="true" size="58"/>

<script type="text/javascript">
  $(document).ready(function(){

    //jquery script
    $("#emp_mat").change(function(){

      var emp_mat = $(this).val();
    $.ajax({
        url:"emp_info.php",
        dataType:'json',
        data:{data:emp_mat}
      }).done(function(result)
      {
        $("#nom_prenom").val(result[0]);
        $("#adresse").val(result[1]);

      })
    });

  });
</script>

<input type="text" id="nom_prenom"   disabled="true" size="58"/>
<input type="text" id="adresse"   disabled="true" size="58"/>

Veuillez ** [modifier] votre réponse **,et ajouter uneexplication: **pourquoi ** celapourrait-il résoudre leproblème?

Please **[edit] your answer**, and add an explanation: **why** could that solve the problem?
- 0
- 2018-07-26
- fuxia

M-R · Accepted Answer · 2013-07-26

2

2013-07-26

Sije comprends correctement,vous devez lesenvelopper dans untableauet passer à Javascript.

 function get_ldap_attr() {
    header("Content-type: application/json");
    ...

    // suppose you want to return $second_var
    echo json_encode(array($sup,$second_var));
    die();  
}

Lafonction de succès de la requête JSON les recevra sousforme detableau. Vouspouvez y accéder avec unindexentier.

 jQuery(function() {
    jQuery('#empLanId').on('blur', function() {
        var lan = jQuery('#empLanId').val();
        var ajaxurl = '<?php echo admin_url("admin-ajax.php", null); ?>';
        var data = { action: "get_ldap", lan: lan};
        jQuery.ajax({
            type: 'POST',
            url: ajaxurl,
            data: data,
            dataType: 'json',
            success: function(response) {
                response[0] // first $sup variable
                response[1] // second $second_var variable
                //jQuery('#empSupLanId').val(response.lanid);
                //jQuery('#empSupName').val(response.fullname);
                //jQuery('#empSupNumber').val(response.phone);
            }
        });
    });
});

If I get it correctly, You need to wrap them in an array and pass to Javascript.

function get_ldap_attr() {
    header("Content-type: application/json");
    ...

    // suppose you want to return $second_var
    echo json_encode(array($sup,$second_var));
    die();  
}

Success function of JSON request will receive them as array. You can access them with integer index.

jQuery(function() {
    jQuery('#empLanId').on('blur', function() {
        var lan = jQuery('#empLanId').val();
        var ajaxurl = '<?php echo admin_url("admin-ajax.php", null); ?>';
        var data = { action: "get_ldap", lan: lan};
        jQuery.ajax({
            type: 'POST',
            url: ajaxurl,
            data: data,
            dataType: 'json',
            success: function(response) {
                response[0] // first $sup variable
                response[1] // second $second_var variable
                //jQuery('#empSupLanId').val(response.lanid);
                //jQuery('#empSupName').val(response.fullname);
                //jQuery('#empSupNumber').val(response.phone);
            }
        });
    });
});