Comment lister uniquement les termes enfants d'une taxonomie et non leurs parents?

Cela devraitfonctionnerpour vous:

 $taxonomyName = "age";
//This gets top layer terms only.  This is done by setting parent to 0.  
$parent_terms = get_terms( $taxonomyName, array( 'parent' => 0, 'orderby' => 'slug', 'hide_empty' => false ) );   
echo '<ul>';
foreach ( $parent_terms as $pterm ) {
    //Get the Child terms
    $terms = get_terms( $taxonomyName, array( 'parent' => $pterm->term_id, 'orderby' => 'slug', 'hide_empty' => false ) );
    foreach ( $terms as $term ) {
        echo '<li><a href="' . get_term_link( $term ) . '">' . $term->name . '</a></li>';   
    }
}
echo '</ul>';
 

This should work for you:

$taxonomyName = "age";
//This gets top layer terms only.  This is done by setting parent to 0.  
$parent_terms = get_terms( $taxonomyName, array( 'parent' => 0, 'orderby' => 'slug', 'hide_empty' => false ) );   
echo '<ul>';
foreach ( $parent_terms as $pterm ) {
    //Get the Child terms
    $terms = get_terms( $taxonomyName, array( 'parent' => $pterm->term_id, 'orderby' => 'slug', 'hide_empty' => false ) );
    foreach ( $terms as $term ) {
        echo '<li><a href="' . get_term_link( $term ) . '">' . $term->name . '</a></li>';   
    }
}
echo '</ul>';

Vouspouvez égalementfaire:

 $terms = get_terms($taxonomyName);
foreach($terms as $term) {
    if ($term->parent != 0) { // avoid parent categories
        //your instructions here
    }
}
 

J'ai remarqué que leparent a le champ "parent" égal à 0,et qu'unenfant a sonidentifiant deparent dedans.

You could also do:

$terms = get_terms($taxonomyName);
foreach($terms as $term) {
    if ($term->parent != 0) { // avoid parent categories
        //your instructions here
    }
}

I've noted that parent have "parent" field equal to 0, and a child have his parent id in it.

Nouspouvonsexclure lesparents deniveau supérieuren lesfiltranten utilisant les terms_clauses filtrepourmodifier la requête SQL avant sonexécution. De cettefaçon,nousn'avonspasbesoin d'ignorer lesparents dans labouclefinale foreach carilsne sontpas dans letableau determes renvoyé,celanous évite untravailet un codageinutiles

Vouspouvezessayer ce qui suit:

 add_filter( 'terms_clauses', function (  $pieces, $taxonomies, $args )
{
    // Check if our custom arguments is set and set to 1, if not bail
    if (    !isset( $args['wpse_exclude_top'] ) 
         || 1 !== $args['wpse_exclude_top']
    )
        return $pieces;

    // Everything checks out, lets remove parents
    $pieces['where'] .= ' AND tt.parent > 0';

    return $pieces;
}, 10, 3 );
 

Pourexclure lesparents depremierniveau,nouspouvonsmaintenantpasser 'wpse_exclude_top' => 1 avecnotretableau d'arguments. Lenouveauparamètre wpse_exclude_topestprisen chargepar lefiltre ci-dessus

 $terms = get_terms( 'category', ['wpse_exclude_top' => 1] );
if (    $terms
     && !is_wp_error( $terms )
) {
    echo '<ul>';
        foreach ($terms as $term) {
            echo '<li><a href="' . get_term_link( $term ) . '">' . $term->name . '</a></li>';  
        }
    echo '</ul>';
}
 

Juste une remarque, get_term_link() fairenonn'acceptepas lenom duterme,uniquement,le slug,l'ID ou leterme objet complet. Pour lesperformances,transmetteztoujours leterme objet à get_term_link() si leterme objetest disponible ( comme dans ce cas )

We can exclude the top level parents by filtering them out by using the terms_clauses filter to alter the SQL query before it executes. This way we do not need to skip parents in the final foreach loop as they are not in the returned array of terms, this saves us unnecessary work and coding

You can try the following:

add_filter( 'terms_clauses', function (  $pieces, $taxonomies, $args )
{
    // Check if our custom arguments is set and set to 1, if not bail
    if (    !isset( $args['wpse_exclude_top'] ) 
         || 1 !== $args['wpse_exclude_top']
    )
        return $pieces;

    // Everything checks out, lets remove parents
    $pieces['where'] .= ' AND tt.parent > 0';

    return $pieces;
}, 10, 3 );

To exclude top level parents, we can now pass 'wpse_exclude_top' => 1 with our array of arguments. The new wpse_exclude_top parameter is supported by the filter above

$terms = get_terms( 'category', ['wpse_exclude_top' => 1] );
if (    $terms
     && !is_wp_error( $terms )
) {
    echo '<ul>';
        foreach ($terms as $term) {
            echo '<li><a href="' . get_term_link( $term ) . '">' . $term->name . '</a></li>';  
        }
    echo '</ul>';
}

Just a note, get_term_link() do no not accept the term name, only, slug, ID or the complete term object. For performance, always always pass the term object to get_term_link() if the term object is available (as in this case)

  $ ages=get_terms (tableau (
    'taxonomie'=>'âge',
    'sansenfant'=>vrai
    )
);
 

Why can't you just set the childless argument to true?

$ages = get_terms( array(
    'taxonomy' => 'age',
    'childless' => true
    )
);

Si vous affichez l'enfant deplusieursparents,vouspouvezessayer ceci.Afficher lesidentifiants duterme dementiontermeenfant.

 $termIds = array(367, 366, 365, 364, 363, 362);
$taxonomyName = "age";

$args = array(
    'orderby'           => 'term_id', 
    'order'             => 'DESC',                      
    'hide_empty'        => false,                       
    'childless'         => false,
); 

$terms = get_terms( $taxonomyName, $args );

if ( ! empty( $terms ) && ! is_wp_error( $terms ) ){
$inc = 1;
foreach ( $terms as $term ) {                           
 if (in_array($term->parent, $termIds)) {
  echo '<option value="'.$term->term_id.'"><font><font>'.$term->name.'</font></font></option>';
    }
  }
}
 

If you display multiple parent's child, you can try this. Display mention term ids child term.

$termIds = array(367, 366, 365, 364, 363, 362);
$taxonomyName = "age";

$args = array(
    'orderby'           => 'term_id', 
    'order'             => 'DESC',                      
    'hide_empty'        => false,                       
    'childless'         => false,
); 

$terms = get_terms( $taxonomyName, $args );

if ( ! empty( $terms ) && ! is_wp_error( $terms ) ){
$inc = 1;
foreach ( $terms as $term ) {                           
 if (in_array($term->parent, $termIds)) {
  echo '<option value="'.$term->term_id.'"><font><font>'.$term->name.'</font></font></option>';
    }
  }
}