Sorties de shortcode en haut du_contenu

Toutes lesfonctions doivent renvoyer une chaîne,vousne devez utiliser echonullepart. Réécrivez lesfonctions,utilisez une variableinternepourgérer les chaîneset renvoyez cela:

 // Output a single menu item
function projects_menu_entry($id, $title, $link_self)
{
    global $blog_id;
    $out = '';

    if ($link_self || $id != $blog_id) {
        $out .= '<li>';
        if ($id == $blog_id) {
            $out .= '<strong>';
        }
        $url = get_home_url( $id, '/' );

        $out .= '<a href="' . $url . '">' . $title . '</a>';
        if ($id == $blog_id) {
            $out .= '</strong>';
        }

        $out .= '</li>';
    }

    return $out;
}

// Output the whole menu
// If $link_self is false, skip the current site - used to display the menu on the homepage
function projects_menu($link_self = true)
{
    global $wpdb;
    $out = '<ul>';

    $out .= projects_menu_entry(1, 'Home', $link_self);

    $blogs = $wpdb->get_results("
        SELECT blog_id
        FROM {$wpdb->blogs}
        WHERE site_id = '{$wpdb->siteid}'
        AND spam = '0'
        AND deleted = '0'
        AND archived = '0'
        AND blog_id != 1
    ");

    $sites = array();
    foreach ($blogs as $blog) {
        $sites[$blog->blog_id] = get_blog_option($blog->blog_id, 'blogname');
    }

    natsort($sites);
    foreach ($sites as $blog_id => $blog_title) {
        $out .= projects_menu_entry($blog_id, $blog_title, $link_self);
    }
    $out .= '</ul>';

    return $out;
}

// Adds a [bloglist] shortcode

function bloglist_shortcode($atts)
{
    return projects_menu(false);
}

add_shortcode('bloglist', 'bloglist_shortcode');
 

Pour unexemple similaireet étendu,voir: Comment renvoyer le contenu de laboucle .

All functions have to return a string, you should not use echo anywhere. Rewrite the functions, use an internal variable to handle the strings and return that:

// Output a single menu item
function projects_menu_entry($id, $title, $link_self)
{
    global $blog_id;
    $out = '';

    if ($link_self || $id != $blog_id) {
        $out .= '<li>';
        if ($id == $blog_id) {
            $out .= '<strong>';
        }
        $url = get_home_url( $id, '/' );

        $out .= '<a href="' . $url . '">' . $title . '</a>';
        if ($id == $blog_id) {
            $out .= '</strong>';
        }

        $out .= '</li>';
    }

    return $out;
}

// Output the whole menu
// If $link_self is false, skip the current site - used to display the menu on the homepage
function projects_menu($link_self = true)
{
    global $wpdb;
    $out = '<ul>';

    $out .= projects_menu_entry(1, 'Home', $link_self);

    $blogs = $wpdb->get_results("
        SELECT blog_id
        FROM {$wpdb->blogs}
        WHERE site_id = '{$wpdb->siteid}'
        AND spam = '0'
        AND deleted = '0'
        AND archived = '0'
        AND blog_id != 1
    ");

    $sites = array();
    foreach ($blogs as $blog) {
        $sites[$blog->blog_id] = get_blog_option($blog->blog_id, 'blogname');
    }

    natsort($sites);
    foreach ($sites as $blog_id => $blog_title) {
        $out .= projects_menu_entry($blog_id, $blog_title, $link_self);
    }
    $out .= '</ul>';

    return $out;
}

// Adds a [bloglist] shortcode

function bloglist_shortcode($atts)
{
    return projects_menu(false);
}

add_shortcode('bloglist', 'bloglist_shortcode');

For a similar, extended example see: How to return loop contents.

Vousne pouvezpas remplacer lesinstances de echo car vousne pouvez revenir qu'une seulefois.Vous devez créer une chaîneet la renvoyer.

 function projects_menu_entry($id, $title, $link_self)
{
    global $blog_id;
    $ret = '';
    if ($link_self || $id != $blog_id) {
        $ret .= '<li>';
        if ($id == $blog_id) {
            $ret .= '<strong>';
        }
    // and so on
    $ret .= '</ul>';
    return $ret;
}
 

Faites celapour les deuxfonctionset jem'attendrais à ce que celafonctionne.Toutesmesexcuses sij'aimal lu quelque chose.

You can't replace the instances of echo because you can only return once. You need to build a string and return that.

function projects_menu_entry($id, $title, $link_self)
{
    global $blog_id;
    $ret = '';
    if ($link_self || $id != $blog_id) {
        $ret .= '<li>';
        if ($id == $blog_id) {
            $ret .= '<strong>';
        }
    // and so on
    $ret .= '</ul>';
    return $ret;
}

Do that for both functions and I would expect this to work. Apologies if I have grossly misread something.

Desidées?Oùest lafonction qui doit être retournée au lieu de écho?

Je vais vousproposer une solution alternative quine vous obligepas à remplacer lesinstances d'écho ou à créer une chaîne de retour.

Vouspouvez activer lamiseen mémoiretampon de sortieet renvoyer letampon sousforme de chaîne.

Ajoutez ob_start() au début de lafonction avanttout appel d'écho.

à lafin de lafonction ajouter:

 $response = ob_get_contents();
ob_end_clean();
return $response;
 

Any ideas? Where is the function that needs to be returned instead of echoed?

I'm going to offer an alternative solution that does not require you to replace instances of echo or build a return string.

You can turn on output buffering and return the buffer as a string.

Add ob_start() to the beginning of the function before any echo call.

at the end of the function add:

$response = ob_get_contents();
ob_end_clean();
return $response;

Réponse courteet rapide:

Vous devez return votre sortieet non la echo.

 $output = 'first';
$output .= 'second'; //notice the dot (.=) after the first variable
$output .= 'third';
return $output;
 

Short and quick answer:

You should return your output and not echo it.

$output = 'first';
$output .= 'second'; //notice the dot (.=) after the first variable
$output .= 'third';
return $output;